Physics High School

## Answers

**Answer 1**

**Answer:**

**B = μ I / (2 * R) magnetic field at center of current carrying loop**

**I1 / R1 = I2 / R2 and we want to know R2**

**R2 = I2 / I1 * R1 = 29 / 10 * 01 = .029 m**

## Related Questions

Explain E=mc2 in Short And Easy Definition

### Answers

It means mass can be converted into energy.

I. E. In a nuclear fission, we start of with a greater mass of our rectant, which then decrease due to mass being converted into the (thermal) energy released, in our reaction. Later, being used to produce electricity, for example.

**Hope this helps! **

A force of 40 N is required to hold a spring that has been stretched from its natural length of 10 cm to a length of 15 cm. How much work is done in stretching the spring from 15 cm to 18 cm

### Answers

**0.36 J** of **work** is **done** in stretching the spring from 15 cm to 18 cm.

To find the correct answer, we need to know about the **work done to strech a string**.

What is the work required to strech a string?Mathematically, the work done to strech a string is given as **1/2 ×K×x². **K is the **spring constant**.What will be the spring constant, if 40N force is required to hold a 10 cm to 15 cm streched spring?The **force experienced by a streched spring** is given as **Kx**. **x** is the length of the spring **streched** from its natural length. Then K = Force / x. Here x = 15 - 10 = 5 cm = 0.05 m**K** = 40/0.05 = **800N/m**.What will be the work required to strech that spring from 15 cm to 18 cm?**Work done = 1/2×k×x²**Here x= 18-15=3cm or **0.03 m**So, W= 1/2×800×0.03² = **0.36 J.**

Thus, we can conclude that the work done is **0.36 J.**

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What's the velocity of a ball falling with 100 jules of kinetic energy and a mass of 2 kilograms?

### Answers

**Answer:**

v = 10m/s.

**Explanation:**

100 = 1/2×2×v^2

100 = 1×v^2

v^2 = √100

v=10 m/s

A source generates 40 waves per sec. if the wavelength is 8 cm. calculate the time waves takes to reach a wall 120m from the source?

### Answers

**Answer:**

37.5 Seconds

**Explanation: Speed = frequency * Wavelength**

**We can find the Frequency by the information given, Frequency = waves per second .**

**40 Waves per second, = 40 Hz**

**Wavelength = 8cmCm = M8cm/100 = 0.08m**

**Speed = 40 Hz * 0.08mSpeed = 3.2m/s**

**Speed = Distance / time takenTime = Distance / Speed**

**Time = 120 / 3.2**

**Time = 37.5 seconds**

What is the velocity ratio of the inclined plane h 9 L 12 hypothesis 15 bellow? A. 1.25 B. 0.60 C. 1.67 D. 0.80

### Answers

B is the answer

hope this helps u

:)

A 43-kg child sits in a massless swing. With what horizontal force must the seat be pulled so that the ropes form an angle of 35o with respect to the vertical? Group of answer choices 300 N 320 N 340 N 360 N

### Answers

The **horizontal force** that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is **345.2 N.**

Horizontal force to be applied

The **horizontal force** that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is calculated as;

F = Wcosθ

where;

W is weight of the childθ is angle of inclination of the rope

F = (43 x 9.8) x cos(35)

F = 345.2 N

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If you take a given pendulum to the Moon, where the acceleration of gravity is less than on Earth, the resonant frequency of the pendulum will Group of answer choices

### Answers

The resonant frequency will** decrease.**

The natural frequency of an object, where it typically vibrates with a greater amplitude, is another way to describe the** resonant frequency.**

The formula for time period of pendulum(T) is

T= 2π[tex]\sqrt{} \frac{l}{g}[/tex] where,

l= **length **of pendulum

g = **acceleration** due to gravity

So, T is **inversely** proportional to the **square root** of g(√g)

It means as the value of g **decreases**, time period of pendulum **increases** and vice versa.

As it is given, value of** g** is less on moon than on earth and it is approx. **6 times** less than that of earth.

That's why time period of oscillation of pendulum **increases.**

Now, as we know that time period is** inversely** proportional to the **frequency**.

So as the time period of pendulum on the moon increases, its resonant frequency **decreases.**

Hence, If we take a given pendulum to the Moon, where the acceleration of gravity is less than on Earth, the resonant frequency of the pendulum will **decrease.**

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The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?.

### Answers

The **speed** of **tsunami** isa.0.32 km.

**Steps** **involved** :

The equation s = 356d models the maximum **speed** that a **tsunami** can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

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Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another and ends up as what?

### Answers

**Answer:**

**Absorbed solar radiation** undergoes irreversible degradations, transferring from reservoir to another converting from **light energy** to **radiation energy**.

**Explanation:**

The **solar energy cycle** functions in the following form:

Considering that 100% of energy is directed at earth.When 100% light is incident on the Earth's surface about **6-7% **of it is **reflected back by the atmosphere into space.****20%** is **reflected back** by the **clouds.**And about **4%** is **reflected back by Earth's surface.****16%** of solar energy is **absorbed by the atmosphere**, **3%** is **absorbed by clouds** and **51%** is **absorbed by land and ocean.**From the absorbed energy, **64%** is **radiated back** to space from **clouds** **and atmosphere** and **6%** is directly **radiated back** to space from **earth**.From the radiated energy **15% is absorbed by the atmosphere** and **23% is carried by the clouds and atmosphere** through the latent heat in water vapor.

Therefore, **absorbed solar radiation** undergoes irreversible degradations, transferring from reservoir to another converting from **light energy** to **radiation energy**.

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A satellite orbits the earth at a speed of 8.0x 10^3m/s . Calculate the period of orbit of the satellite if the distance between the centre of the earth and the satellite is 6400km?

### Answers

Hi there!

The **period of an orbit** can be found by:

[tex]T = \frac{2\pi r}{v}[/tex]

T = Period (? s)

r = radius of orbit (6400000 m)

v = speed of the satellite (8000 m/s)

This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.

Let's plug in what we know and solve.

[tex]T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}[/tex]

In which of the following scenarios is the total momentum of the system conserved?

### Answers

Answer:

The total momentum of a system is conserved only when the system is closed.

Explanation:

What is the formula for the moment of inertia of the person/single particle rotating in a circle? (Give these values with a subscript of 1, e.i. I1 = ) What is this value of the moment of inertia when the person is on the edge of the merry-go-round?

### Answers

**Moment of inertia** of **single particle rotating in circle **is I1 = 1/2 (m*r^2)

The value of the **moment of inertia** when the person is on the **edge of the merry-go-round** is I2=1/3 (m*L^2)

**Moment of Inertia** refers to:

the quantity expressed by the body resisting angular acceleration.It the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

The moment of inertia of single particle rotating in a circle **I1 = 1/2 (m*r^2)**

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with **parallel-axis theorem**:

**I(edge) = I (center of mass) + md^2**

d be the distance from an axis through the object’s center of mass to a new axis.

**I2(edge) = 1/3 (m*L^2)**

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what provides the centiperal force to a satellite revolving around the earth?

### Answers

**Answer:**

the gravitational force

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1869 N to the right. What is the acceleration of the crate?

a=(6.0 or 6.00 or 8.10 or 8.1)=m/s^2

### Answers

The **acceleration** of the steel crate, given the data from the question is **6.0 m/s²**

How to determine the net forceForce to the left (Fբ) = 480 NForce to the right (Fᵣ) = 1869 N**Net force (Fₙ) = ?**

Fₙ = Fᵣ - Fբ

Fₙ = 1869 - 480

**Fₙ = ****1****3****8****9**** ****N**

How to determine the accelerationMass (m) = 230 KgNet force (Fₙ) = 1389 N**Acceleration ****(****a****)**** ****= ?**

Fₙ = ma

Divide both sides by m

a = Fₙ / m

a = 1389 / 230

**a**** ****=**** ****6****.****0**** ****m****/****s****²**

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LSST stands for Long Space Standard Telescope.

True

Or False

### Answers

think the answer is false

A person who normally weighs 580 N is riding in an elevator that is moving upward, but slowing down at a steady rate. If this person is standing on a bathroom scale inside the elevator, what would the scale read

### Answers

**Answer:**

**M au = Fs - M g au = upwards acceleration; Fs = scale reading**

**Fs = M (au + g) scalar quantities where g is positive downwards and au is positive upwards - Fs is the net force acting on the person**

**If the acceleration is zero Fs = M g and the scale reads the persons weight**

**If the elevator is decelerating then au is negative and the scale reading Fs = (g - au) M and the scale reading is less than the weight of the person**

A 5.0 kg box slides down a 4.0 m long ramp that makes a 25 angle with the ground. If the coefficient of kinetic friction is 0.65, how much thermal energy was produced?

### Answers

The **thermal energy** was produced is** 116J**

What is the thermal energy produced?

Now we know that the **frictional force** produces the energy that is lost as heat as the** body slides **down the **incline**. The **magnitude **of the **frictional force** is obtained from;

Ff= μmgcosθ

Ff = 0.65 * 5.0 kg * 9.8 m/s^2 * cos 25

Ff = **29 N**

Hence, the thermal energy is;

29 N * 4.0 m =** 116J**

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An effective display of trend and magnitude is achieved by using a combination of a _____. Group of answer choices time series plot and sparklines line chart and trendlines heat map and sparklines bubble chart and trendlines

### Answers

An effective display of trend and magnitude is achieved by using a combination of a C)**heat map** and **sparklines.**

While the **standard** **chart** is designed to expose as a great deal fact as possible and is set off from the float of text, **sparklines** are meant to be succinct, memorable, and located in which they are mentioned.

A heatmap (or warmness map) is a **graphical** **illustration** of facts wherein values are depicted through color. They are crucial in detecting what does or does not paintings on a website or product page.

A warmth map **visualization** is a mixture of nested, colored rectangles, each representing an attribute detail. Heat Maps are regularly used inside the monetary services industry to review the reputation of a **portfolio**.

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The pilot of the fighter jet turns by banking the wings such that the lift of the wings has a component in

the direction of the centre of the turn. The pilot wishes to turn the jet in a tight radius of 960.0 m while

maintaining a constant circular speed of 1440 km/h. Determine the angle of bank needed, measured from

the vertical.

### Answers

The **angle **of **bank **needed, measured from the **vertical **is **86.6⁰.**

**Banking angle of the circular path**

The **angle **of **bank **needed, measured from the vertical is calculated as follows;

v = √(rg tanθ)

where;

v is the speed = 1440 km/h = 400 m/sr is radius of the curve = 960 mg is acceleration due to gravityθ is the banking angle

400² = (960 x 9.8 x tanθ)

tanθ = 400²(960 x 9.8)

tanθ = 17

θ = arc tan(17)

θ = 86.6⁰

Thus, the **angle **of **bank **needed, measured from the **vertical **is **86.6⁰.**

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The force of gravity, just as all forces, is an action on an object. Forces appear due to the interactions between pairs of objects. Therefore, for the force of gravity to act on a falling object, there should be another object that, in a sense, is creating that force. Which object is responsible for creating the force of gravity observed on falling objects

### Answers

**The Earth as a whole **is responsible for creating the force of gravity observed on falling objects.

How is earth responsible?

As the **earth** pulls the objects lower due to its gravity, the objects typically fall towards the earth by **Gravitational force.**

The law of **gravitation** states that the force of attraction between any two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. Anywhere in the universe, the law is applicable to objects. One claims that this law is ubiquitous.

The mass and density of the planet, 5.97237 1024 kg (1.31668 1025 lbs) and 5.514 g/cm3, respectively, determine the force of Earth's gravity. Because of this, **Earth** has a **gravitational** pull of 9.8 m/s2 at its surface or 1 g. This pull naturally weakens the further one goes from the surface.

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A circular solenoid contains 100 turns of wire and carries a current of 2 A. Its radius is 1 cm and its length is 10 cm. Calculate the magnetic flux through one turn of the wire making the solenoid.

### Answers

The **magnetic flux** through one turn of the wire making the solenoid is **7.88*10^-7 T m^2**.

B = unI

= 4pi*10^-7*(100/0.1)*2

= 0.00251 T

Therefore, **Flux** = B*Area

= 0.00251*pi*(0.01^2)

= 7.88*10^-7 T m^2

Magnetic flux is a measurement of the entire **magnetic** discipline which passes thru a given **vicinity**. It's far a useful device for helping describe the outcomes of the magnetic pressure on something occupying a given vicinity. The size of the **magnetic** **flux** is tied to the specific location chosen.

The SI unit of magnetic flux is the **Weber** (Wb). A flux density of 1 Wb/m2 (one Weber in keeping with rectangular meter) is one **Tesla** (T).

A magnetic subject describes a location in which a **magnetic pressure** may be felt. Magnetic flux describes how a good deal of magnetic discipline passes through a place.

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7. Suppose a force of 15 N is required to stretch and hold a spring 0.25 m from its equilibrium position. a. Assuming the spring obeys Hooks law, find the spring constant k. b. How much work is required to compress the spring 0.2 m from its equilibrium position

### Answers

**Spring constant ** k = 75 N/m

**Hooke's law **for this spring **F(x) = 75x**

**Work **= 1.5 J

**What is work?**When an object is moved over a distance by an **external force**, at least a portion of that force must be applied in the direction of the displacement. This is known as **work**.The **amount of work** required to **move an object** down a line from point a to point b in the direction of a **variable force F** is

[tex]$W=\int_{a}^{b} F(x) d x$[/tex]

First solution

According to **Hooke's law**, the **spring** must be held stretched at x=0.2m by a **force** of 15N.

F (0.2) = k (0.2 m) = 15 N

Solve for** k**

k = 75 N/m

Hence, Hooke's law is **F(x) = 75x**

Second solution

The spring is compressed from x = 0 to X = 0.2,

[tex]$W=\int_{0}^{0.2} 75 x d x=\left.\left(\frac{75 x^{2}}{2}\right)\right|_{0} ^{0.2}$[/tex]

W = 1.5 J

So, the **work** is required to compress the **spring 0.2 m** from its **equilibrium position** W = 1.5 J

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A piano of mass 852 kg is lifted to a height of 3.5 m. How much gravitational potential energy is added to the piano? Acceleration due to gravity is g = 9.8

m/g2

### Answers

**Answer:**

Gravitational Potential Energy = Mass*Gravity*Height.

GPE = 852 * 9.8 * 3.2

GPE = 26718.72 Newtons.

An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equivalent spring constant of the bow

### Answers

**Answer: **An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

**Explanation: **To find the answer, we have to know about the** Simple Harmonic Motion**.

What is Simple Harmonic Motion?A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force. The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.If x is the displacement from the mean position, and F is the restoring force, then

[tex]F[/tex]∝[tex]-x[/tex]

[tex]F=-kx[/tex] where, k is called the spring constant.

How to approach the problem?Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.Here, from the question given, we can write, [tex]x=-0.400m[/tex] and [tex]F=230N[/tex].Thus, our spring constant k will be,

[tex]k=-F/x= (230)/ (0.400) =575 N/m.[/tex]

Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.

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A key falls from a bridge that is 43 m above the water. It falls directly into a model boat, moving with constant velocity, that is 17 m from the point of impact when the key is released. What is the speed of the boat

### Answers

The **speed** of the boat is **4 m/s.**

The system for pace is **speed** = distance ÷ time.

To work out what the devices are for pace, you want to understand the gadgets for distance and time. In this case, **distance** is in meters (m) and **time** is in seconds (s), so the gadgets could be in meters according to second (m/s).

To resolve for speed or price use the components for pace, s = d/t which means that pace equals **distance** divided through **time**.

The pace is a manner of measuring how quickly something is transferring or being performed, or something moving **speedily**. An example of speed is a vehicle being driven 45 miles in keeping with the hour. An instance of velocity is a person cleaning a room in 10 minutes. An example of velocity is how quickly a jaguar runs.

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A stone of mass 150g is rotated in a horizontal circle at 10m/s which is attached to the end of a 1m long. what will be the acceleration of the stone and it's centripetal force?

### Answers

force is mass multiply by acceleration so it will be 150 multiply by 10 is 1500N

**Answer:**

Acceleration: [tex]100\; {\rm m\cdot s^{-2}}[/tex] assuming that the radius of the rotation is [tex]1\; {\rm m}[/tex].

Centripetal force: [tex]15\; {\rm N}[/tex].

**Explanation:**

In a circular motion, if the tangential velocity is [tex]v[/tex] and the radius of the motion is [tex]r[/tex], the centripetal acceleration of the motion would be [tex]a = (v^{2} / r)[/tex].

In this question, it is implied that for this circular motion, [tex]v = 10\; {\rm m\cdot s^{-1}}[/tex] while [tex]r = 1\; {\rm m}[/tex]. Thus, the (centripetal) acceleration would be:

[tex]\begin{aligned} a &= \frac{v^{2}}{r} \\ &= \frac{(10\; {\rm m\cdot s^{-2}})^{2}}{1\; {\rm m}} \\ &= 100\; {\rm m \cdot s^{-2}}\end{aligned}[/tex].

Note that the unit of mass in this question is gram, whereas the standard unit for mass should be [tex]{\rm kg}[/tex] (so as to leverage the fact that [tex]1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}}[/tex].) Apply unit conversion: [tex]m = 150\; {\rm g} = 0.150\; {\rm kg}[/tex].

Using that fact that [tex](\text{net force}) = (\text{mass}) \, (\text{acceleration})[/tex]:

[tex]\begin{aligned} (\text{net force}) &= (\text{mass}) \, (\text{acceleration}) \\ &= 0.150\; {\rm kg} \times 100\; {\rm m\cdot s^{-2}} \\ &= 15\; {\rm kg \cdot m \cdot s^{-2}} \\ &= 15\; {\rm N}\end{aligned}[/tex].

A spring whose spring constant is 260 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 in. The work required to compress it another 1 in is Btu.

### Answers

The **work** **required** to compress it another 1 in Btu is **0.02463 Btu.**

Work finished is elaborated in the sort of way that it consists of both forces exerted at the frame and the full **displacement** of the body. This block is preceded by a steady force F. The reason for this pressure is to transport the frame a sure **distance** d in an instant course in the direction of the force.

To explicit this idea mathematically, the **work** W is the same as the pressure f instances the distance d, or W = FD. If the **pressure** is being exerted at a perspective θ to the **displacement**, the work finished is W = FD cos θ.

The work is executed whenever a force actions something over a distance. you can calculate the **electricity** **transferred**, or work completed, by multiplying the force by way of the space moved inside the course of the force.

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You are working on a laboratory device that includes a small sphere with a large electric charge Q. Because of this charged sphere, there is a strong electric field surrounding your device. Other researchers in your laboratory are complaining that your electric field is affecting their equipment. You think about how you can obtain the large electric field that you need close to the sphere but prohibit the field from reaching your colleagues. You decide to surround your device with a spherical transparent plastic shell. The nonconducting shell is given a uniform charge distribution. (a) The shell is placed so that the small sphere is at the exact center of the shell. Determine the charge that must be placed on the shell to completely eliminate the electric field outside of the shell. (Use any variable or symbol stated above as necessary.) 9 = x Your argument should be based on the use of Gauss's law to ensure the absence of an electric field outside the combination.

### Answers

a) q_shell = -Q , b) q_shell = -Q

a) We can solve this exercise using **Gauss's law**

** Ф = ∫ E. dA = /ε₀**

For this we use a Gaussian surface that takes advantage of the symmetry of the problem, we select a sphere where this force of the spherical plastic shell.

In this case, the electric field lines coincide with the radii of the sphere and the scalar product reduces to the algebraic product, the area of the sphere

** A = 4 π r²**

**fi = E 4π r² = q_{int} /ε₀**

apply this formula to our case, we have that the charge inside the Gaussian sphere is

** q_{int} = q_sphere + q_shell**

the charge of the sphere is Q and the requirement is that there is no electric field outside the Gaussian sphere, for this, the net charge inside it must be zero

0 = Q + q_shell

** q_shell = -Q**

b) In Gauss's law, only the charge inside the Gaussian surface matters, not its position, therefore if the charge is not in the center the result remains the same.

** q_shell = -Q**

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what is specific latent heat mean in simple word?

### Answers

**Answer:**

Amount of energy required to change the 1kg of a substance without changing its temperature.

which two forms of energy do burning substances produce

### Answers

**Answer:**thermal (heat) energy and radiant (light) energy.

**Explanation:**

**Answer:**

Answer: We use the chemical energy in fuels by burning them and transforming them into other types of energy: thermal energy, as when we burn fuel for heat; and kinetic energy, as when we burn gasoline to power our car's motion

**Explanation:**

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