The Magnetic Field At The Center Of Two Concentric Current Loops Is Zero. The Smaller Loop Has A Radius (2024)

It means mass can be converted into energy.

I. E. In a nuclear fission, we start of with a greater mass of our rectant, which then decrease due to mass being converted into the (thermal) energy released, in our reaction. Later, being used to produce electricity, for example.

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0.36 J of work is done in stretching the spring from 15 cm to 18 cm.

To find the correct answer, we need to know about the work done to strech a string.

What is the work required to strech a string?Mathematically, the work done to strech a string is given as 1/2 ×K×x². K is the spring constant.What will be the spring constant, if 40N force is required to hold a 10 cm to 15 cm streched spring?The force experienced by a streched spring is given as Kx. x is the length of the spring streched from its natural length. Then K = Force / x. Here x = 15 - 10 = 5 cm = 0.05 mK = 40/0.05 = 800N/m.What will be the work required to strech that spring from 15 cm to 18 cm?Work done = 1/2×k×x²Here x= 18-15=3cm or 0.03 mSo, W= 1/2×800×0.03² = 0.36 J.

Thus, we can conclude that the work done is 0.36 J.

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Answer:

v = 10m/s.

Explanation:

100 = 1/2×2×v^2

100 = 1×v^2

v^2 = √100

v=10 m/s

Answer:

37.5 Seconds

Explanation:
Speed = frequency * Wavelength

We can find the Frequency by the information given, Frequency = waves per second .

40 Waves per second, = 40 Hz

Wavelength = 8cm
Cm = M
8cm/100 = 0.08m

Speed = 40 Hz * 0.08m
Speed = 3.2m/s

Speed = Distance / time taken
Time = Distance / Speed

Time = 120 / 3.2

Time = 37.5 seconds

B is the answer

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The horizontal force that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is 345.2 N.

Horizontal force to be applied

The horizontal force that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is calculated as;

F = Wcosθ

where;

W is weight of the childθ is angle of inclination of the rope

F = (43 x 9.8) x cos(35)

F = 345.2 N

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The resonant frequency will decrease.

The natural frequency of an object, where it typically vibrates with a greater amplitude, is another way to describe the resonant frequency.

The formula for time period of pendulum(T) is

T= 2π[tex]\sqrt{} \frac{l}{g}[/tex] where,

l= length of pendulum

g = acceleration due to gravity

So, T is inversely proportional to the square root of g(√g)

It means as the value of g decreases, time period of pendulum increases and vice versa.

As it is given, value of g is less on moon than on earth and it is approx. 6 times less than that of earth.

That's why time period of oscillation of pendulum increases.

Now, as we know that time period is inversely proportional to the frequency.

So as the time period of pendulum on the moon increases, its resonant frequency decreases.

Hence, If we take a given pendulum to the Moon, where the acceleration of gravity is less than on Earth, the resonant frequency of the pendulum will decrease.

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The speed of tsunami isa.0.32 km.

Steps involved :

The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

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Answer:

Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

Explanation:

The solar energy cycle functions in the following form:

Considering that 100% of energy is directed at earth.When 100% light is incident on the Earth's surface about 6-7% of it is reflected back by the atmosphere into space.20% is reflected back by the clouds.And about 4% is reflected back by Earth's surface.16% of solar energy is absorbed by the atmosphere, 3% is absorbed by clouds and 51% is absorbed by land and ocean.From the absorbed energy, 64% is radiated back to space from clouds and atmosphere and 6% is directly radiated back to space from earth.From the radiated energy 15% is absorbed by the atmosphere and 23% is carried by the clouds and atmosphere through the latent heat in water vapor.

Therefore, absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

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Hi there!

The period of an orbit can be found by:

[tex]T = \frac{2\pi r}{v}[/tex]

T = Period (? s)
r = radius of orbit (6400000 m)

v = speed of the satellite (8000 m/s)

This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.

Let's plug in what we know and solve.

[tex]T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}[/tex]

Answer:

The total momentum of a system is conserved only when the system is closed.

Explanation:

Moment of inertia of single particle rotating in circle is I1 = 1/2 (m*r^2)

The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)

Moment of Inertia refers to:

the quantity expressed by the body resisting angular acceleration.It the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:

I(edge) = I (center of mass) + md^2

d be the distance from an axis through the object’s center of mass to a new axis.

I2(edge) = 1/3 (m*L^2)

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Answer:

the gravitational force

The acceleration of the steel crate, given the data from the question is 6.0 m/s²

How to determine the net forceForce to the left (Fբ) = 480 NForce to the right (Fᵣ) = 1869 NNet force (Fₙ) = ?

Fₙ = Fᵣ - Fբ

Fₙ = 1869 - 480

Fₙ = 1389 N

How to determine the accelerationMass (m) = 230 KgNet force (Fₙ) = 1389 NAcceleration (a) = ?

Fₙ = ma

Divide both sides by m

a = Fₙ / m

a = 1389 / 230

a = 6.0 m/s²

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Answer:

M au = Fs - M g au = upwards acceleration; Fs = scale reading

Fs = M (au + g) scalar quantities where g is positive downwards and au is positive upwards - Fs is the net force acting on the person

If the acceleration is zero Fs = M g and the scale reads the persons weight

If the elevator is decelerating then au is negative and the scale reading Fs = (g - au) M and the scale reading is less than the weight of the person

The thermal energy was produced is 116J

What is the thermal energy produced?

Now we know that the frictional force produces the energy that is lost as heat as the body slides down the incline. The magnitude of the frictional force is obtained from;

Ff= μmgcosθ

Ff = 0.65 * 5.0 kg * 9.8 m/s^2 * cos 25

Ff = 29 N

Hence, the thermal energy is;

29 N * 4.0 m = 116J

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An effective display of trend and magnitude is achieved by using a combination of a C)heat map and sparklines.

While the standard chart is designed to expose as a great deal fact as possible and is set off from the float of text, sparklines are meant to be succinct, memorable, and located in which they are mentioned.

A heatmap (or warmness map) is a graphical illustration of facts wherein values are depicted through color. They are crucial in detecting what does or does not paintings on a website or product page.

A warmth map visualization is a mixture of nested, colored rectangles, each representing an attribute detail. Heat Maps are regularly used inside the monetary services industry to review the reputation of a portfolio.

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The angle of bank needed, measured from the vertical is 86.6⁰.

Banking angle of the circular path

The angle of bank needed, measured from the vertical is calculated as follows;

v = √(rg tanθ)

where;

v is the speed = 1440 km/h = 400 m/sr is radius of the curve = 960 mg is acceleration due to gravityθ is the banking angle

400² = (960 x 9.8 x tanθ)

tanθ = 400²(960 x 9.8)

tanθ = 17

θ = arc tan(17)

θ = 86.6⁰

Thus, the angle of bank needed, measured from the vertical is 86.6⁰.

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The Earth as a whole is responsible for creating the force of gravity observed on falling objects.

How is earth responsible?

As the earth pulls the objects lower due to its gravity, the objects typically fall towards the earth by Gravitational force.

The law of gravitation states that the force of attraction between any two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. Anywhere in the universe, the law is applicable to objects. One claims that this law is ubiquitous.

The mass and density of the planet, 5.97237 1024 kg (1.31668 1025 lbs) and 5.514 g/cm3, respectively, determine the force of Earth's gravity. Because of this, Earth has a gravitational pull of 9.8 m/s2 at its surface or 1 g. This pull naturally weakens the further one goes from the surface.

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The magnetic flux through one turn of the wire making the solenoid is 7.88*10^-7 T m^2.

B = unI

= 4pi*10^-7*(100/0.1)*2

= 0.00251 T

Therefore, Flux = B*Area

= 0.00251*pi*(0.01^2)

= 7.88*10^-7 T m^2

Magnetic flux is a measurement of the entire magnetic discipline which passes thru a given vicinity. It's far a useful device for helping describe the outcomes of the magnetic pressure on something occupying a given vicinity. The size of the magnetic flux is tied to the specific location chosen.

The SI unit of magnetic flux is the Weber (Wb). A flux density of 1 Wb/m2 (one Weber in keeping with rectangular meter) is one Tesla (T).

A magnetic subject describes a location in which a magnetic pressure may be felt. Magnetic flux describes how a good deal of magnetic discipline passes through a place.

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Spring constant k = 75 N/m

Hooke's law for this spring F(x) = 75x

Work = 1.5 J

What is work?When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work.The amount of work required to move an object down a line from point a to point b in the direction of a variable force F is

[tex]$W=\int_{a}^{b} F(x) d x$[/tex]

First solution

According to Hooke's law, the spring must be held stretched at x=0.2m by a force of 15N.

F (0.2) = k (0.2 m) = 15 N

Solve for k

k = 75 N/m

Hence, Hooke's law is F(x) = 75x

Second solution

The spring is compressed from x = 0 to X = 0.2,

[tex]$W=\int_{0}^{0.2} 75 x d x=\left.\left(\frac{75 x^{2}}{2}\right)\right|_{0} ^{0.2}$[/tex]

W = 1.5 J

So, the work is required to compress the spring 0.2 m from its equilibrium position W = 1.5 J

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Answer:

Gravitational Potential Energy = Mass*Gravity*Height.

GPE = 852 * 9.8 * 3.2

GPE = 26718.72 Newtons.

Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

Explanation: To find the answer, we have to know about the Simple Harmonic Motion.

What is Simple Harmonic Motion?A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force. The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.If x is the displacement from the mean position, and F is the restoring force, then

[tex]F[/tex]∝[tex]-x[/tex]

[tex]F=-kx[/tex] where, k is called the spring constant.

How to approach the problem?Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.Here, from the question given, we can write, [tex]x=-0.400m[/tex] and [tex]F=230N[/tex].Thus, our spring constant k will be,

[tex]k=-F/x= (230)/ (0.400) =575 N/m.[/tex]

Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.

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The speed of the boat is 4 m/s.

The system for pace is speed = distance ÷ time.

To work out what the devices are for pace, you want to understand the gadgets for distance and time. In this case, distance is in meters (m) and time is in seconds (s), so the gadgets could be in meters according to second (m/s).

To resolve for speed or price use the components for pace, s = d/t which means that pace equals distance divided through time.

The pace is a manner of measuring how quickly something is transferring or being performed, or something moving speedily. An example of speed is a vehicle being driven 45 miles in keeping with the hour. An instance of velocity is a person cleaning a room in 10 minutes. An example of velocity is how quickly a jaguar runs.

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force is mass multiply by acceleration so it will be 150 multiply by 10 is 1500N

Answer:

Acceleration: [tex]100\; {\rm m\cdot s^{-2}}[/tex] assuming that the radius of the rotation is [tex]1\; {\rm m}[/tex].

Centripetal force: [tex]15\; {\rm N}[/tex].

Explanation:

In a circular motion, if the tangential velocity is [tex]v[/tex] and the radius of the motion is [tex]r[/tex], the centripetal acceleration of the motion would be [tex]a = (v^{2} / r)[/tex].

In this question, it is implied that for this circular motion, [tex]v = 10\; {\rm m\cdot s^{-1}}[/tex] while [tex]r = 1\; {\rm m}[/tex]. Thus, the (centripetal) acceleration would be:

[tex]\begin{aligned} a &= \frac{v^{2}}{r} \\ &= \frac{(10\; {\rm m\cdot s^{-2}})^{2}}{1\; {\rm m}} \\ &= 100\; {\rm m \cdot s^{-2}}\end{aligned}[/tex].

Note that the unit of mass in this question is gram, whereas the standard unit for mass should be [tex]{\rm kg}[/tex] (so as to leverage the fact that [tex]1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}}[/tex].) Apply unit conversion: [tex]m = 150\; {\rm g} = 0.150\; {\rm kg}[/tex].

Using that fact that [tex](\text{net force}) = (\text{mass}) \, (\text{acceleration})[/tex]:

[tex]\begin{aligned} (\text{net force}) &= (\text{mass}) \, (\text{acceleration}) \\ &= 0.150\; {\rm kg} \times 100\; {\rm m\cdot s^{-2}} \\ &= 15\; {\rm kg \cdot m \cdot s^{-2}} \\ &= 15\; {\rm N}\end{aligned}[/tex].

The work required to compress it another 1 in Btu is 0.02463 Btu.

Work finished is elaborated in the sort of way that it consists of both forces exerted at the frame and the full displacement of the body. This block is preceded by a steady force F. The reason for this pressure is to transport the frame a sure distance d in an instant course in the direction of the force.

To explicit this idea mathematically, the work W is the same as the pressure f instances the distance d, or W = FD. If the pressure is being exerted at a perspective θ to the displacement, the work finished is W = FD cos θ.

The work is executed whenever a force actions something over a distance. you can calculate the electricity transferred, or work completed, by multiplying the force by way of the space moved inside the course of the force.

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a) q_shell = -Q , b) q_shell = -Q

a) We can solve this exercise using Gauss's law

Ф = ∫ E. dA = /ε₀

For this we use a Gaussian surface that takes advantage of the symmetry of the problem, we select a sphere where this force of the spherical plastic shell.

In this case, the electric field lines coincide with the radii of the sphere and the scalar product reduces to the algebraic product, the area of ​​the sphere

A = 4 π r²

fi = E 4π r² = q_{int} /ε₀

apply this formula to our case, we have that the charge inside the Gaussian sphere is

q_{int} = q_sphere + q_shell

the charge of the sphere is Q and the requirement is that there is no electric field outside the Gaussian sphere, for this, the net charge inside it must be zero

0 = Q + q_shell

q_shell = -Q

b) In Gauss's law, only the charge inside the Gaussian surface matters, not its position, therefore if the charge is not in the center the result remains the same.

q_shell = -Q

Please check the attached attachment for the detailed answer.

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Answer:

Amount of energy required to change the 1kg of a substance without changing its temperature.

Answer:thermal (heat) energy and radiant (light) energy.

Explanation:

Answer:

Answer: We use the chemical energy in fuels by burning them and transforming them into other types of energy: thermal energy, as when we burn fuel for heat; and kinetic energy, as when we burn gasoline to power our car's motion

Explanation:

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